def sleep_in(weekday, vacation):
if weekday == ['monday', 'tuesday', 'wednesday', 'thursday', 'friday'] and vacation == 'Yes':
return True
elif weekday != ['monday', 'tuesday', 'wednesday', 'thursday', 'friday'] or vacation == 'Yes':
return True
else:
return False
print(sleep_in('monday', 'No'))
Here's some better code:
def sleep_in(weekday, vacation):
if vacation:
return True
if weekday in ['monday', 'tuesday', 'wednesday', 'thursday', 'friday']:
return False
else:
return True
This code works because it first checks vacation
, and returns True
when vacation is true (you can simply do if vacation
for this).
Next, if vacation is false, it evaluates the next if
statement, and sees whether the weekday parameter is within the list of ['monday', 'tuesday', 'wednesday', 'thursday', 'friday']
. If it is, it returns False (no sleep_in). If it is not, it means it's a weekend and sleep_in returns true.
I think that's the goal you were trying to achieve.