Using '\r' to replace a number in for loop in C

I need to have a for loop counter that should replace the number with a text when it's divisible by a set of numbers. I already have the loop and the code working, but the '\r' in my printf function does not work someone else's compiler.

Here is my code and outputs from different compilers so you can identify the issue better.

#include <stdio.h>

void hey(void)
{
    
    for (int i = 50; i <= 100; i++)
    {
        printf("%d", i);

        if (i % 5 == 0)
        {

            printf("\rHEY1 ");
        }
        if (i % 40 == 0)
        {

            printf("\rHEY2 ");
        }
        if (i % 40 == 0 && i % 5 == 0)
        {

            printf("\rHEY3 ");
        }

        printf("\n");
    }
}

int main(void)
{
    hey();
    return 0;
}

This's the result on my compiler, which is how I exactly want:

My output

and this one is how it appears on the online compiler that my teacher uses to mark:

Other output

For some reason, it doesn't remove the number to replace with 'Hey' in the other compiler. Instead, prints it on a new line.

How do I fix this? It should remove the number and print the letters instead of it as it's on the first screenshot. TIA.

Solution

I suspect that your teacher does not expect you to use '\r' and instead expects you to figure out how NOT to output the number in the first place and instead right away print the "HEY". That would be reliable in all environments.

Her is how you can do that. Note that I used else if and that I reordered the checks, in order to get what I am sure is what you want for case 80.
I also simplified the 80 condition, because the reordering allows that.
I chose the "HEY3" option for 80. You will never find "HEY2" AND "HEY3" in an output of this code, because anythign divisible by 40 is always also divisible by 5.


#include <stdio.h>

void hey(void)
{
    
    for (int i = 50; i <= 100; i++)
    {
        if (i % 40 == 0 /* && i % 5 == 0 */)
        {

            printf("HEY3 ");
        } else if (i % 5 == 0)
        {

            printf("HEY1 ");
        } /* else if (i % 40 == 0)
        {
            printf("HEY2 ");
        } */ else  
        {
            printf("%d", i);
        }

        printf("\n");
    }
}

int main(void)
{
    hey();
    return 0;
}

Output: