I am sure this I am missing the point. Simple code:
from itertools import combinations_with_replacement
p1 = combinations_with_replacement("2357",3)
y = [''.join(i) for i in p1]
print (y)
Produces: ['222', '223', '225', '227', '233', '235', '237', '255', '257', '277', '333', '335', '337', '355', '357', '377', '555', '557', '577', '777']
I am looking to find all possible ways of pulling 3 from the 4 digits - where order matters. In my case, 755 is not returned as 557 has the same digits.
I am looking for: ['222','223','232' (new), '225', 252' (new) ] etc
Currently the use of combinations_with_replacement rejects sequences where the numbers have been previously drawn. I probably need "permutations" (but with replace) which seems to be missing.
What am I overlooking?
Cheers
Use itertools.product since you seem to be looking for the entire cartesian product pool X pool X pool:
from itertools import product
p1 = product("2357", repeat=3)
y = [*map(''.join, p1)]
print(y)