I am trying to concatenate the string like below
typedef struct IInfo
{
char cmAddress[6];
UINT8 IpAddress[4];
UINT8 hIpAddress[4];
} IInfo;
In my file:
IInfo Info;
char CableIP[50];
__android_log_print(ANDROID_LOG_DEBUG,"test","test--> %s:%d IpAddress[0] : %d,IpAddress[1] : %d,IpAddress[2] : %d,IpAddress[3] : %d\n", __FUNCTION__, __LINE__, Info.IpAddress[0], Info.IpAddress[1],Info.IpAddress[2], Info.IpAddress[3]);
strcpy(CableIP,Info.IpAddress[0]);//10
strcat(CableIP,"." );
strcat(CableIP,Info.IpAddress[1] );//1
strcat(CableIP,"." );
strcat(CableIP,Info.IpAddress[2] );//120
strcat(CableIP,"." );
strcat(CableIP,Info.IpAddress[3] );//36
printf("CableIP %s",CableIP);
getting print like below: test: test--> _ExecuteFUN:298 IpAddress[0] : 10,IpAddress[1] : 1,IpAddress[2] : 120,IpAddress[3] : 36
Expecting output is 10.1.120.36
but getting below error F libc : Fatal signal 11 (SIGSEGV), code 1, fault addr 0xa in tid 2888 (n0000001)
An individual array element print getting proper data, but if I do concatenation getting an error.
can you please suggest to me, where I have done wrong?
char *strcpy(char *restrict dest, const char *src);
The
strcpy()
function copies the string pointed to bysrc
, including the terminating null byte ('\0'
), to the buffer pointed to bydest
. - For more
Info.IpAddress
is of type array of UINT8
rather than char*
.
I would prefer as following
sprintf(CableIP, "%u.%u.%u.%u%c", Info.IpAddress[0], Info.IpAddress[1], Info.IpAddress[2], Info.IpAddress[3], '\0');