I have a list of text like this format-
2021-07-11 18:34:24,381: Mouse clicked at (159, 88) with Button.left
Here, I want to search this "(159, 88)" pattern with the bracket from my entire text file.
The 1st and 2nd values in the parenthesis can be One digit to four digits. I mean this format can be (1, 888) or (20, 32) or (134, 4) or (365, 567) or (1240, 122) or (1345, 1245).
Now, by using regex, how do I solve this problem?
My expected output is- (384, 567)
Please help.
Use the pattern '\(\d+,\s*\d+\)' to match the substring you want.
>>> import re
>>> text = '2021-07-11 18:34:24,381: Mouse clicked at (159, 88) with Button.left'
>>> re.findall('\(\d+,\s*\d+\)', text)
['(159, 88)']
Understanding the pattern: '\(\d+,\s*\d+\)'
\( : Look for opening parenthesis, \ is used as escape character
\d+ : Look for one or more digits
, : Look for exactly one comma
\s* : Zero or more white space characters
\d+ : Look for one or more digits again
\) : Look for closing parenthesis, \ is used as escape character