Python associate function

Question

I want to add the file extensions found in the function to the line of code where I specified "HERE". In other words, not only ".txt", but also the extensions of the above function should be brought that part. In short, I want to associate the following code with the function.

Can you help me, with this?

def extention_finder(file_path):
    
    if ".XLSX" in file_path.upper():
        ext = ".xlsx"
    elif ".XLS" in file_path.upper():
        ext = ".xls"
    elif ".TXT" in file_path.upper():
        ext = ".txt"
    elif ".CSV" in file_path.upper():
        ext = ".csv"
    elif ".XLT" in file_path.upper():
        ext = ".xlt"
    elif ".zip" in file_path.upper():
        ext = ".zip"    
    else:
        ext = "N/A"



counts = 1
myZip = zipfile.ZipFile(path_to_zip_file)
print(myZip.namelist())

for file in myZip.filelist:
    if file.filename.endswith(".txt"):        # HERE HERE HERE HERE HERE HERE
        if os.path.basename(file.filename) in os.listdir(directory_to_extract_to):
            source = myZip.open(file)
            target = open(os.path.join(directory_to_extract_to, os.path.basename(file.filename).split(".")[0] + "_" + str(counts) + "." + os.path.basename(file.filename).split(".")[1]), "wb")
            counts = counts + 1 
            
        else:
            source = myZip.open(file)
            target = open(os.path.join(directory_to_extract_to, os.path.basename(file.filename)), "wb")

            with source, target:
                shutil.copyfileobj(source, target)

Answer 1

Assuming that the only . in the string file_path is the one that starts the file extension, this rewrite of your function should do the job:

def extension_finder(file_path):
    paths = ["XLSX", "XLS", "TXT", "CSV", "XLT", "ZIP"]
    return file_path.split(".")[1].upper() in paths

Then in the if statement you can call extension_finder with the path you want to check.