I am working with the R programming language.
I am trying to define a grid using the "expand.grid" command, where the grid "self references" itself:
random_1 <- seq(80,100,5)
random_2 <- seq(random_1,120,5)
random_3 <- seq(85,120,5)
random_4 <- seq(random_3,120,5)
split_1 = seq(0,1,0.5)
split_2 = seq(0,1,0.5)
split_3 = seq(0,1,0.5)
DF_2 <- expand.grid(random_1 , random_2, random_3, random_4, split_1, split_2, split_3)
But this returns the following error:
Error in seq.default(random_3, 120, 5) : 'from' must be of length 1
>
Does anyone know how to fix this error?
Thanks
seq
takes a single element as from
, to
. According to ?seq
from, to - the starting and (maximal) end values of the sequence. Of length 1 unless just from is supplied as an unnamed argume
We could loop over the 'random_1'
lapply(random_1, function(x) seq(x, 120, 5))
Do the same for random_3
and construct as
> random_2 <- lapply(random_1, function(x) seq(x, 120, 5))
> random_3 <- seq(85,120,5)
> random_4 <- lapply(random_3, function(x) seq(x, 120, 5))
> split_1 = seq(0,1,0.5)
> split_2 = seq(0,1,0.5)
> split_3 = seq(0,1,0.5)
> DF_2 <- expand.grid(c(list(random_1), random_2, random_3, random_4, list(split_1, split_2, split_3)))