Would like to seek your help on creating simple bat file that will copy specific file from source to destination. Eg.
Source = C:\Source
Dest = D:\Destination
File in source:
123.CSV
234.CSV
456.CSV
567.CSV
678.CSV
789.CSV
012.CSV
and I only want to copy the ff:
123.CSV
456.CSV
678.CSV
012.CSV
and delete others after copying.
Script:
@ECHO OFF
CHCP 65001 > NUL
FOR /F "usebackq delims=" %%I IN ("G:\SOURCE\123.CSV") DO (
xcopy /s "G:\SOURCE\123%%I" "G:\DESTINATION\%%I*"
)
PAUSE
Thank you for your help in advance
This works fine. Or one big long ROBOCOPY command. robocopy "G:\SOURCE" "G:\DESTINATION" "123.CSV" "456.CSV" "678.CSV" "012.CSV" – @squashman