Find an duplicate items at position in 2d list in python

I have a 2d list of route numbers and coordinates that I've produced from out of a KML file. The order is 'routenumber','coordinates' e.g.:

[['90', '54.93920,25.52,0.0'], ['93', '37.326,19.39,0.0'], ['94', '-110.67,24.395,0.0'], ['95', '-102.154599,17.915081,0.0'], ['96', '-109.177574,25.537,0.0'], ['97', '54.93920,25.52,0.0'], ['98', '55.319,25.506,0.0'], ['911', '54.939206,25.5249,0.0'], ['914', '54.93920,25.52,0.0'], ['915', '54.9169,25.5031,0.0'], ['916', '55.3709,25.35949,0.0'], ['917', '54.939206,25.5249,0.0'], ['920', '56.4641,25.21,0.0'], ['921', '56.4916,25.376,0.0']]

For each route in the list I'm trying to find routes with the same coordinates e.g.

Output:
54.939206,25.5249,0.0 is seen in 911, 917
54.93920,25.52,0.0 is seen in 90, 97, 914

so at a simple level something that can identify duplicates in the second inner? 'column' of

[['1','10'],['2','50'],['3','10'],['4','0'],['5','50']]

and provide me with:

Output:
10 is seen in 1, 3
50 is seen in 2, 5

I have tried the following but am now tying myself in knots and wondering if I should be using a dictionary instead. I'm fairly new to python as you can probably tell. Nothing that I can find on the forums here talks about comparing a specific item at a position in a 2d list (which makes me wonder about using a dictionary)

for idx, (route,mcoords) in enumerate(endcoordlist):
    #print(idx, route, coords)
    if any(mcoords in coords for idx, (route,coords) in enumerate(endcoordlist)):    
        print(idx, route, coords)

Any help would be greatly appreciated.

UPDATE: Thanks to sushanth for the code. I have adapted it slightly for readability/noobs like me to understand what's going on.

for v in endcoordlist:
    if groups.get(v[1]):
        print(v[0]," is a duplicate with coordinates:",v[1])
        groups[v[1]].append(v[0])
    
    else:
        groups[v[1]] = [v[0]]
        print(v[1]," is unique")

for k, v in groups.items():
    print(f"{k} seen in {','.join(v)}")

Solution

Here is a solution you can give it a try,

Declare a dict considering coordinates as the key & route as list of values for the dict.

groups = {}

for v in input_:
    if groups.get(v[1]):
        groups[v[1]].append(v[0])
    else:
        groups[v[1]] = [v[0]]

for k, v in groups.items():
    print(f"{k} seen in {','.join(v)}")

54.93920,25.52,0.0 seen in 90,97,914
37.326,19.39,0.0 seen in 93
...