I have 2 arrays
or more likely NodeLists
,
const mainSlides = document.querySelectorAll('.mainSlides')
const thumbSlides = document.querySelectorAll('.thumbSlides')
Currently i am iterating over them like this:
mainSlides.forEach(slide => {
slide.style.backgroundColor = `red`
})
thumbSlides.forEach(slide => {
slide.style.backgroundColor = `red`
})
Since they both set the same property ie; background-color:red;
, is there a shorthand way to loop through both nodelists at once?
const mainSlides = document.querySelectorAll('.mainSlides')
const thumbSlides = document.querySelectorAll('.thumbSlides')
mainSlides.forEach(slide => {
slide.style.backgroundColor = `red`
})
thumbSlides.forEach(slide => {
// slide.style.backgroundColor = `red`
})
<div class="holder">
<div class="mainSlides"> some mainSlides </div>
<div class="mainSlides"> some mainSlides </div>
<div class="mainSlides"> some mainSlides </div>
<div class="mainSlides"> some mainSlides </div>
</div>
<div class="holder">
<div class="thumbSlides"> some mainSlides </div>
<div class="thumbSlides"> some mainSlides </div>
<div class="thumbSlides"> some mainSlides </div>
<div class="thumbSlides"> some mainSlides </div>
</div>
You can select both mainSlides
and thumbSlides
like so:
const allSlides = document.querySelectorAll('.mainSlides, .thumbSlides');
Or, if you don't want to select them together (e.g. if you want to use them further separately) but just want to use them together for this specific action:
const allSlides = [...mainSlides, ...thumbSlides];
allSlides.forEach(slide => {
slide.style.backgroundColor = 'red';
})