How to add values in column by key in nested dictionary of list in python

Question

I have nested dictionary of list.

inputlist= {1: {0: [[1, 20], [6, 20]], 1: [[3, 22], [4, 22]]},
            2: {0: [[2, 21], [7, 21]], 1: [[3, 22], [4, 23]]},
            3: {0: [[5, 23], [8, 22]], 1: [[7, 23], [3, 11]]}}

For each key 1,2 and 3, I want to do addition by column value for each key 0 and 1. Result should be like this:

{1: {0: [(7, 40)] 1: [(7, 44)]},
 2: {0: [(9, 42)] 1: [(7, 45)]},
 3: {0: [(13, 45)] 1: [(10, 34)]}}

Here what have I tried:

sum_result={}
for k1, v1 in inputlist.items():
    for (k2,v2) in v1.items():
        sum_result+= v2
    print (sum_result)

Answer 1

try the following code to get your expected output:

inputlist= {1: {0: [[1, 20], [6, 20]], 1: [[3, 22], [4, 22]]},
            2: {0: [[2, 21], [7, 21]], 1: [[3, 22], [4, 23]]},
            3: {0: [[5, 23], [8, 22]], 1: [[7, 23], [3, 11]]}}

sum_result= dict()
for k1, v1 in inputlist.items():
    sum = []
    temp = {}
    for (k2,v2) in v1.items():
        sum = [v2[0][0]+v2[1][0], v2[0][1]+v2[1][1]]
        temp[k2] = sum
    sum_result[k1] = temp

print(sum_result)

Output:

{
   1: {0: [7, 40], 1: [7, 44]}, 
   2: {0: [9, 42], 1: [7, 45]}, 
   3: {0: [13, 45], 1: [10, 34]}
}