I am having a logical issue with evaluating Tic-Tac-Toe winning conditions

Question

I have been working on a Tic-Tac-Toe game and part of the winning logic is I decided to store conditional statements for winning (ie. three in a row, three in column, or three diagonal) in constant variables. The problem I am facing is that boolean False is the result of all the statements I did. I have proof with prints I inserted into my program.

Code:

# Create game cells
list = [' ' for n in range(10)]

# Coniditions for winning
O_ROW = (
    (list[1] == 'O' and list[2] == 'O' and list[3] == 'O') or
    (list[4] == 'O' and list[5] == 'O' and list[6] == 'O') or
    (list[7] == 'O' and list[8] == 'O' and list[9] == 'O')
)
O_COL = (
    (list[1] == 'O' and list[4] == 'O' and list[7] == 'O') or
    (list[2] == 'O' and list[5] == 'O' and list[8] == 'O') or
    (list[3] == 'O' and list[6] == 'O' and list[9] == 'O')
)
X_ROW = (
    (list[1] == 'X' and list[2] == 'X' and list[3] == 'X') or
    (list[4] == 'X' and list[5] == 'X' and list[6] == 'X') or
    (list[7] == 'X' and list[8] == 'X' and list[9] == 'X')
)
X_COL = (
    (list[1] == 'X' and list[4] == 'X' and list[7] == 'X') or
    (list[2] == 'X' and list[5] == 'X' and list[8] == 'X') or
    (list[3] == 'X' and list[6] == 'X' and list[9] == 'X')
)
O_DIAG = (
    (list[1] == 'O' and list[5] == 'O' and list[9] == 'O') or
    (list[3] == 'O' and list[5] == 'O' and list[7] == 'O')
)
X_DIAG = (
    (list[1] == 'X' and list[5] == 'X' and list[9] == 'X') or
    (list[3] == 'X' and list[5] == 'X' and list[7] == 'X')
)

def displayBoard():
    # Printing the game board
    print()
    print(f'\t {list[1]} | {list[2]} | {list[3]}')
    print('\t-----------')
    print(f'\t {list[4]} | {list[5]} | {list[6]}')
    print('\t-----------')
    print(f'\t {list[7]} | {list[8]} | {list[9]}')
    print()

def playBoard(pos, pl):
    # Position the play in the cell and check for already-placed cells
    if list[pos] != 'X' and list[pos] != 'O':
        list[pos] = pl.upper()
    else:
        print("Already played! Try again")

    # Determine winning condition or tie
    if O_ROW and O_COL and O_DIAG:
        print("O Wins!")
        sys.exit()
    elif X_ROW and X_COL and X_DIAG:
        print("X Wins!")
        sys.exit()


print('''Welcome to the game of Tic-Tac-Toe.
You will pick a play (X or O) and then pick from a place of 1 to 9 on
the board. Let's begin
''')

# Print for debugging
print(X_ROW)
print(X_COL)
print(X_DIAG)
print(O_ROW)
print(O_COL)
print(O_DIAG)

Output:

Welcome to the game of Tic-Tac-Toe.
You will pick a play (X or O) and then pick from a place of 1 to 9 on
the board. Let's begin

False
False
False
False
False
False
Play X or O?

What is the problem with the logic that they all evaluate to False?

If the reason for this logic error is encapsulating conditional statements into variables/constants, then pardon my ignorance. I tried to do this because the literal conditional statements all within the if statements later in the code looked too long and hard to read.

Answer 1

You are not upadting the values, so it's false everytime. You can do someting like this.

import sys
# Create game cells
List = ['-' for n in range(10)]


# Coniditions for winning
def runGame():
    O_ROW = (
        not(List[1] == 'O' and List[2] == 'O' and List[3] == 'O') or
        not(List[4] == 'O' and List[5] == 'O' and List[6] == 'O') or
        not(List[7] == 'O' and List[8] == 'O' and List[9] == 'O')
    )
    O_COL = (
        not(List[1] == 'O' and List[4] == 'O' and List[7] == 'O') or
        not(List[2] == 'O' and List[5] == 'O' and List[8] == 'O') or
        not(List[3] == 'O' and List[6] == 'O' and List[9] == 'O')
    )
    O_DIAG = (
        not(List[1] == 'O' and List[5] == 'O' and List[9] == 'O') or
        not(List[3] == 'O' and List[5] == 'O' and List[7] == 'O')
    )
    X_ROW = (
        not(List[1] == 'X' and List[2] == 'X' and List[3] == 'X') or
        not(List[4] == 'X' and List[5] == 'X' and List[6] == 'X') or
        not(List[7] == 'X' and List[8] == 'X' and List[9] == 'X')
    )
    X_COL = (
        not(List[1] == 'X' and List[4] == 'X' and List[7] == 'X') or
        not(List[2] == 'X' and List[5] == 'X' and List[8] == 'X') or
        not(List[3] == 'X' and List[6] == 'X' and List[9] == 'X')
    )
    X_DIAG = (
        not(List[1] == 'X' and List[5] == 'X' and List[9] == 'X') or
        not(List[3] == 'X' and List[5] == 'X' and List[7] == 'X')
    )
    return(O_DIAG,O_ROW,O_COL,X_ROW,X_DIAG,X_COL)

def displayBoard():
    # Printing the game board
    print()
    print(f'\t {List[1]} | {List[2]} | {List[3]}')
    print('\t-----------')
    print(f'\t {List[4]} | {List[5]} | {List[6]}')
    print('\t-----------')
    print(f'\t {List[7]} | {List[8]} | {List[9]}')
    print()

def playBoard(pos, pl):
    # Position the play in the cell and check for already-placed cells
    if List[pos] != 'X' and List[pos] != 'O':
        List[pos] = pl.upper()
    else:
        print("Already played! Try again")

    # Determine winning condition or tie
    if not runGame()[0] or not runGame()[1] or not runGame()[2]  :
        displayBoard()
        print("O Wins!")
        sys.exit()
        
    elif not runGame()[3] or not runGame()[4] or not runGame()[5]:
        displayBoard()
        print("X Wins!")
        sys.exit()
    elif "-" not in List:
        print("It's a draw")
        sys.exit()


print('''Welcome to the game of Tic-Tac-Toe.
You will pick a play (X or O) and then pick from a place of 1 to 9 on
the board. Let's begin
''')

while (all(runGame())):
    displayBoard()
    pos=int(input("pos"))
    p1=input("X/O")
    playBoard(pos,p1)
    


playBoard(pos,p1)