Here I have tried to code addition of two single variable polynomials in c++ . The code runs fine when both the inputs are in sync with the other . But when it ain't it shows some crazy stuff happening and prints complete gibberish . I am pasting my code here with the output . Any suggestions would be helpful .
My Code
#include <iostream>
using namespace std;
class Term
{
public :
int coeff;
int exp;
};
class Poly
{
private:
int n;
Term *terms;
public:
Poly(int n)
{
this->n = n;
terms = new Term[n];
}
void create();
void Display();
Poly* add(Poly &p2);
~Poly()
{
delete []terms;
}
};
void Poly::create()
{
cout << "Enter Terms " << endl;
for(int i = 0; i<n;i++)
{
cin >> terms[i].coeff >> terms[i].exp ;
}
}
void Poly::Display()
{
for(int i = 0;i<n;i++)
{
cout <<terms[i].coeff<<"x"<<terms[i].exp <<" + ";
}
}
Poly* Poly :: add(Poly &p2)
{
int i,j,k;
Poly* sum = new Poly(n+p2.n);
i = j = k = 0 ;
while(i<n && j<p2.n)
{
if(terms[i].exp>p2.terms[j].exp)
{
sum->terms[k++] = terms[i++];
}
else if(terms[i].exp<p2.terms[j].exp)
sum->terms[k++] = terms[j++];
else
sum->terms[k].exp = terms[i].exp;
sum->terms[k++].coeff = terms[i++].coeff +p2.terms[j++].coeff ;
}
for(;i<n;i++)
{
sum->terms[k++] = terms[i];
}
for(;j<p2.n;j++)
{
sum->terms[k++] = p2.terms[j];
}
sum->n = k;
return sum ;
}
int main()
{
int n,m;
cout << "Enter no.of terms for 1st Polynomial" << endl ;
cin >> n;
Poly p1(n);
p1.create();
cout << "Enter no.of terms for 2nd Polynomial" << endl ;
cin >> m ;
Poly p2(m) ;
p2.create();
Poly *p3 ;
p3 = p1.add(p2);
cout << endl;
p1.Display();
cout << endl;
cout << "-------" << endl ;
p2.Display();
cout << endl;
cout << " ------------" << endl ;
p3->Display();
return 0;
}
Output 1:(passing 1st test Case)
Enter no.of terms for 1st Polynomial
5
Enter Terms
2 5
3 4
6 3
7 2
8 1
Enter no.of terms for 2nd Polynomial
5
Enter Terms
3 5
8 4
1 3
5 2
6 1
2x5 + 3x4 + 6x3 + 7x2 + 8x1 +
-------
3x5 + 8x4 + 1x3 + 5x2 + 6x1 +
------------
5x5 + 11x4 + 7x3 + 12x2 + 14x1 +
Process returned 0 (0x0) execution time : 48.853 s
Press any key to continue.
Output II(Failing the Test Case 2)
Enter no.of terms for 1st Polynomial
5
Enter Terms
3 5
2 4
8 3
4 2
6 1
Enter no.of terms for 2nd Polynomial
4
Enter Terms
7 5
4 3
8 1
2 0
3x5 + 2x4 + 8x3 + 4x2 + 6x1 +
-------
7x5 + 4x3 + 8x1 + 2x0 +
------------
10x5 + 2x4 + 12x-1 + 4x2 + 14x0 + 2x0 +
Process returned 0 (0x0) execution time : 56.271 s
Press any key to continue.
Any help suggestions to solve the problem would be appreciated . Thank You .
The main mistake in your code is this line:
sum->terms[k++].coeff = terms[i++].coeff +p2.terms[j++].coeff ;
and, more precisely, its location in the whole routine.
Namely, it is located past the if - else if - else
construct. As a result, it is executed despite exponents satisfy the 'less-than', the 'greater-than' or the 'equal' condition; and it should be done in the last case only.
The relevant part of code should be enclosed with another pair of curly braces:
while(i<n && j<p2.n)
{
if(terms[i].exp>p2.terms[j].exp)
sum->terms[k++] = terms[i++];
else if(terms[i].exp<p2.terms[j].exp)
sum->terms[k++] = terms[j++];
else
{
sum->terms[k].exp = terms[i].exp;
sum->terms[k++].coeff = terms[i++].coeff +p2.terms[j++].coeff ;
}
}
Another error is in the else if
branch: you use the j
index to the this->terms
array:
sum->terms[k++] = terms[j++];
while you should use the p2.terms
:
sum->terms[k++] = p2.terms[j++];