Let I have a code:
for (auto& a : x.as)
{
for (auto& b : a.bs)
{
for (auto& c : b.cs)
{
for (auto& d : c.ds)
{
if (d.e == ..)
{
return ...
}
}
}
}
}
as, bs, cs, ds - std::vector of corresponding elements.
Is it possible with std::ranges to convert four ugly loops into a beatifull one line expression?
With join
and transform
views, you might do:
for (auto& e : x.as | std::views::transform(&A::bs) | std::views::join
| std::views::transform(&B::cs) | std::views::join
| std::views::transform(&C::ds) | std::views::join
| std::views::transform(&D::e))
{
// ...
}