I have a data frame where each observation is comprehended in two columns. In this way, columns 1 and 2 represents the individual 1, 3 and 4 the individual 2 and so on.
Basically what I want to do is to add two contigous columns so I have the individual real score.
In this example V1 and V2 represent individual I and V3 and V4 represent individual II. So for the result data frame I will have the half of columns, the same number of rows and each value will be the addition of each value between two contigous colums.
Data
V1 V2 V3 V4
1 0 0 1 1
2 1 0 0 0
3 0 1 1 1
4 0 1 0 1
Desire Output
I II
1 0 2
2 1 0
3 1 2
4 1 1
I tried something like this
a <- data.frame(V1= c(0,1,0,0),V2=c(0,0,1,1),V3=c(1,0,1,0),V4=c(1,0,1,1))
b <- data.frame(NA, nrow = nrow(a), ncol = ncol(data))
for (i in seq(2,ncol(a),by=2)){
for (k in 1:nrow(a)){
b[k,i] <- a[k,i] + a[k,i-1]
}
}
b <- as.data.frame(b)
b <- b[,-c(seq(1,length(b),by=2))]
Is there a way to make it simplier?
We could use split.default
to split the data and then do rowSums
by looping over the list
sapply(split.default(a, as.integer(gl(ncol(a), 2, ncol(a)))), rowSums)
1 2
[1,] 0 2
[2,] 1 0
[3,] 1 2
[4,] 1 1