So I'm a total Python beginner and I got this byte object:
byte_obj = b'\x45\x10\x00\x4c\xcc\xde\x40\x00\x40\x06\x6c\x80\xc0\xa8\xd9\x17\x8d\x54\xda\x28'
But I have no idea how to put this in a binary number, I only know it's gonna have 32 bits.
You could try int.from_bytes(...)
, documented here e.g.:
>>> byte_obj = b'\x45\x10\x00\x4c\xcc\xde\x40\x00\x40\x06\x6c\x80\xc0\xa8\xd9\x17\x8d\x54\xda\x28'
>>> int.from_bytes(byte_obj, byteorder='big')
394277201243797802270421732363840487422965373480
Where byteorder
is used to specify whether the input is big- or little-endian (i.e. most or least significant byte first).
(Looks a bit bigger than 32 bits though!)