Python3 check if int epochtime are less then X hours diff

Question

I have two ints that represents epochtimes:

x1 = 1597611600
x2 = 1597489203

I want to check if there is less then 72 hours between them. What is the best way to do so in Python3? Please notice that both are int.

Answer 1

You can convert epoch timestamps to datetime objects, perform subtraction and compare the result to timedelta object. However, you can simply do a comparision in seconds.

from datetime import datetime as dt, timedelta as td
def epoch_diff_within(ts1, ts2, hr):
    d1 = dt.fromtimestamp(x1)
    d2 = dt.fromtimestamp(x2)
    return d1 - d2 < td(hours=hr)

def epoch_diff_within2(ts1, ts2, hr):
    return ts1 - ts2 < hr * 60 * 60

x1 = 1597611600
x2 = 1597489203
print(epoch_diff_within(x1, x2, 72)) # Output: True
print(epoch_diff_within2(x1, x2, 72)) # Output: True
print(epoch_diff_within(x1, x2, 24)) # Output: False
print(epoch_diff_within2(x1, x2, 24)) # Output: False