I have this goal:
forall n m : nat, S n > m -> n >= m
The gt_S lemmata would be applicable to prove it but Coq won't unify the two types.
gt_S: forall n m : nat, S n > m -> n > m \/ m = n
What would be the simplest solution here (excluding lia)?
In this case you can use forward reasoning by using apply .. in
rather than plain apply
.
Goal forall n m : nat, S n > m -> n >= m.
Proof.
intros n m h.
apply gt_S in h.
After which hypothesis h
is now h : n > m \/ m = n
.
Hopefully you should be able to progress from there.