Extract phone number and convert to whatsapp format

Question

Im new to python, and I need to use it inside my Zapier automation. In my automation, I want to convert phone numbers from various format to specific format (whatsapp url purpose). How can I extract and convert below inputs to specific output using python?

input:
+62 812-3456-7890
62081234567890
6281234567890
+6281234567890
081234567890
(62)81234567890
(62)081234567890
(+62)81234567890
(+62)081234567890

output:
6281234567890

Additional information: "62" is the country code for Indonesia typically 8-12 digits including a "0" prefixing the "8nn"

Thank you in advance

Answer 1

It is not the most optimal solution, but I wanted to keep it very simple, because you are a beginner in python.

def decode(number: str):
    chars = ['+', '(', ')', '-', ' ']
    for c in chars:
        number = number.replace(c, '')

    return number
        
print(decode('+62 812-3456-7890'))
print(decode('(62)81234567890'))

chars is a list of characters that you want to remove from a number.

EDIT I tried to test every number you gave in the question and I found out that code above doesn't work as you wanted. Here's my new solution and it passes all tests:

def decode(number: str):
    chars = ['+', '(', ')', '-', ' ']
    for c in chars:
        number = number.replace(c, '')

    if number.startswith('0'):
        number = number[1:]
    if not number.startswith('62'):
        number = f'62{number}'
    if number[2] == '0':
        number = number.replace('0', '', 1)

    return number

tests = """+62 812-3456-7890
62081234567890
6281234567890
+6281234567890
081234567890
(62)81234567890
(62)081234567890
(+62)81234567890
(+62)081234567890"""
        
for num in tests.split('\n'):
    print(decode(num))

I added some if statments to handle all tests exeptions and also added test for each test case you gave.

The output of tests:

6281234567890
6281234567890
6281234567890
6281234567890
6281234567890
6281234567890
6281234567890
6281234567890
6281234567890