I created a custom command scan
for the windows terminal which executes a python script.
@echo off
python "my_scripts\scan.py"
For initial tests, I have written this fabulous script.
import sys
print(f"The name of the script is: { sys.argv[0] }")
When I type scan
into the shell, as for as I know, this should just print: The name of the script is: scan
.
But instead, the output I am getting is: The name of the script is: my_scripts\scan.py
.
It´s very obvious what the issue is, but I don´t know how to fix this.
You can use Path.stem
to get the name of a file without the extension
__file__
is the full path to the current file which you can pass to Path
from pathlib import Path
print(f"The name of the script is: {Path(__file__).stem}")
You can also pass sys.argv[0]
instead if you want to
from pathlib import Path
import sys
print(f"The name of the script is: {Path(sys.argv[0]).stem}")