Let's suppose I have a data frame with two columns, one for months and the second one for days. Here is a simple example
month=c(2, 4, ,7, 8, 11, 11, 12)
day=c(21,4,6,8,15,20,30)
monthday=data.frame(month,day)
I want to determine a number (from 1 to 365) that corresponds to the year's day. How can I do that?
You can use the yday
function from the lubridate
package:
library(dplyr)
library(tidyr)
library(lubridate)
month=c(2, 4,7, 8, 11, 11, 12)
day=c(21,4,6,8,15,20,30)
# also define a year so you can parse an actual date
year = 2021
monthday=tibble(month,day, year)
monthday %>%
# combine into one variable
tidyr::unite("date", year, month, day, sep = "-", remove = FALSE) %>%
# parse as date
dplyr::mutate(date = lubridate::ymd(date)) %>%
# extract day of year
dplyr::mutate(doy = lubridate::yday(date))
#> # A tibble: 7 x 5
#> date month day year doy
#> <date> <dbl> <dbl> <dbl> <dbl>
#> 1 2021-02-21 2 21 2021 52
#> 2 2021-04-04 4 4 2021 94
#> 3 2021-07-06 7 6 2021 187
#> 4 2021-08-08 8 8 2021 220
#> 5 2021-11-15 11 15 2021 319
#> 6 2021-11-20 11 20 2021 324
#> 7 2021-12-30 12 30 2021 364
Created on 2021-05-31 by the reprex package (v2.0.0)