I have a tableview cell which contains a specific button for showing alert sheet. I've learned that button itself can't be pressed inside of table view cell. It must be called from a view controller. So I`ve added a callback closure like so:
class FeedViewCell: UITableViewCell {
var callback : (() -> ())?
static let reuseIdentifier: String = "FeedTableViewCell"
lazy var menuButton: UIButton = {
let btn = UIButton()
btn.isUserInteractionEnabled = true
btn.addTarget(self, action: #selector(menuTapped), for: .touchUpInside)
return btn
}()
override init(style: UITableViewCell.CellStyle, reuseIdentifier: String?) {
super.init(style: style, reuseIdentifier: reuseIdentifier)
addSubview(menuButton)
}
@objc func menuTapped() {
print("menu tapped")
callback?()
}
I suspect it might be a problem with table view cell registration.. Pls let me know if that's not it. And in the view controller I did this:
class FeedViewController: UIViewController {
// some code...
tableView.register(FeedViewCell.self, forCellReuseIdentifier: FeedViewCell.reuseIdentifier)
}
extension FeedViewController: UITableViewDelegate, UITableViewDataSource {
func tableView(_ tableView: UITableView, cellForRowAt indexPath: IndexPath) -> UITableViewCell {
let cell = tableView.dequeueReusableCell(withIdentifier: FeedViewCell.reuseIdentifier, for: indexPath) as! FeedViewCell
cell.callback = {
print("menu")
let actionSheet = UIAlertController(title: "", message: "", preferredStyle: .actionSheet)
actionSheet.addAction(UIAlertAction(title: "Dismiss", style: .cancel, handler: { action in
print("tap dismiss")
}))
actionSheet.addAction(UIAlertAction(title: "Follow", style: .default, handler: { action in
print("tap follow")
}))
self.present(actionSheet, animated: true, completion: nil)
}
return cell
}
}
So the main question is, why is the button not working? It doesn't even print "menu"
Thank you for all of your answers
This line is wrong.
addSubview(menuButton)
Instead:
contentView.addSubview(menuButton)