I have a general question regarding listeners.
Lets say I have two JTabbedPane
s and both have a ChangeListener
. They are both displayed and I want them both to show the same pane (index) so when a user changes the selected pane in one the other changes too.
In brief, one JTabbedPane listener changes the other JTabbedPane
using setSelectedTab()
.
Obviously, the first listener will activate the second listener and the second will reactivate the first in an endless operation.
This will be solved with booleans.
Is there a smarter way to do it?
Is there a way to change a tab without triggering the Listener?
Is there a way to activate the listener only when a user changes it and not the code?
Thank you.
BTW: I always have the same questions with buttons. But with buttons I take the code from the listener and put it in a method. when One button needs to activate a button it calls its code. But in JTabbedPane it is different.
The simple solution is to act only when necessary. For example:
if(currentTab != desiredTab) {
// change tab
}
That will prevent an infinite loop.
If you need to be able to switch the behavior on and off, then using a boolean flag isn't a bad way to go about it. The alternative is the remove the listener, using removeChangeListener. The flag may be more performant as it may avoid memory allocation and deallocation, but a lot depends on the other details of your situation.