Printing birthdates using maps and they end up as Octals

If I create a map for names and birthdays. When i enter birthdates that end in 0 it changes it the number to an octal. how do i print out the birthday ie 010525 == 4437 so when i call it -> second it will print 010525

#include <stdio.h>
#include <iterator>
#include <string>
#include <map>
#include <iostream>


using namespace std;

int main(){
    map<string, int>birth;

    birth["Chicken"] = 010525;
    birth["Dragon"] = 010266;


    map<string, int>::iterator it;

    for(it = birth.begin() ; it != birth.end(); it++){
        cout << it -> first + " ";
        cout << it ->second << endl;

    }
}

Output:

Chicken 4437
Dragon 4278

Solution

There are 2 ways to fix this problem:

(1) The first way is to enter the birthday without the leading 0 as follow:

birth["Chicken"] = 10525;
birth["Dragon"] =  10266;

Then use setfill() and setw() to fill the leading 0.

Please note that the code that uses std:setw() and std::setfill() will compile only with new C++ compiler versions such as C++14 (or C++11)

#include <stdio.h>
#include <iterator>
#include <string>
#include <map>
#include <iostream>
#include <iomanip>

using namespace std;

int main(){
    map<string, int>birth;

    birth["Chicken"] = 10525;
    birth["Dragon"] = 10266;


    map<string, int>::iterator it;

    for(it = birth.begin() ; it != birth.end(); it++){
        cout << it -> first + " ";
        cout << setfill('0') << setw(6) << it ->second << endl;

    }
}

(2) The second way is to store the birthday as string. This way you can enter the birthday with the leading 0.

Here is the code:

#include <stdio.h>
#include <iterator>
#include <string>
#include <map>
#include <iostream>


using namespace std;

int main(){
    map<string, string>birth;

    birth["Chicken"] = "010525";
    birth["Dragon"] = "010266";


    map<string, string>::iterator it;

    for(it = birth.begin() ; it != birth.end(); it++){
        cout << it -> first + " ";
        cout << it ->second << endl;

    }
}