I've made a calendar sheet and would like to fill it using an Arrayformula or some kind of Lookup. The problem is, the code in each cell is different, do I need it all to be the same code or is it possible to do an Arrayformula that does a different formula for each line?
I spent ages getting the calendar code working but would now like to simplify the code and I'm not sure what my next step should be:
https://docs.google.com/spreadsheets/d/1u_J7bmOFyDlYXhcL5dW3CHFJ1esySAKK_yPc6nFTdLA/edit?usp=sharing
Any advice would be much appreciated.
I've added a new sheet in your file called 'Aresvik'.
The green cells have new formula.
Cell B3
can be =date(B1,1,1)
Then each successive month can be =eomonth(B3,0)+1
, =eomonth(J3,0)+1
etc.
The date formula in cell B5
is:
=arrayformula(iferror(vlookup(sequence(7,7,1),{array_constrain(sequence(40,1),day(eomonth(B3,0))+weekday(B3,3),1),query({flatten(split(rept(",",day(eomonth(B3,0))-1),",",0,0));sequence(day(eomonth(B3,0)),1,1)},"offset "&day(eomonth(B3,0))-weekday(B3,3)&" ",0)},2,false),))
It can be copied to each other cell below Mo
, so B5
will change to J5
, R5
, Z5
etc.
Notes
The concept revolves around using the SEQUENCE
function to generate a grid of numbers, 6 rows, 7 columns:
sequence(6,7)
which looks like this:
1 2 3 4 5 6 7
8 9 10 11 12 13 14
15 16 17 18 19 20 21
22 23 24 25 26 27 28
29 30 31 32 33 34 35
36 37 38 39 40 41 42
Then using these numbers in a VLOOKUP
to get a corresponding date for the calendar. If the first of the month falls on a Thursday (April 2021), the vlookup range needs 3 gaps at the top of the list of dates. player0 has a more elegant solution than my original query
using offset
, so I've incorporated it below. Cell Z3 is the date 1/4/2021:
=arrayformula(
iferror(
vlookup(sequence(6,7),
{sequence(day(eomonth(Z3,0))+weekday(Z3,2),1,0),
{iferror(sequence(weekday(Z3,2),1)/0,);sequence(day(eomonth(Z3,0)),1,Z3)}},
2,false)
,))
The first column in the vlookup range is:
sequence(day(eomonth(Z3,0))+weekday(Z3,2),1,0)
which is an array of numbers from 0, corresponding with the number of days in the month plus the number of gaps before the 1st day.
The second column in the vlookup range is:
{iferror(sequence(weekday(Z3,2),1)/0,);sequence(day(eomonth(Z3,0)),1,Z3)}},
It is an array of 2 columns in this format: {x;y}
, where y
sits below x
because of the ;
.
These are the gaps: iferror(sequence(weekday(Z3,2),1)/0,)
, followed by the date numbers: sequence(day(eomonth(Z3,0)),1,Z3)
(Example below is April 2021):
0
1
2
3
4
5
6 44317
7 44318
8 44319
9 44320
10 44321
11 44322
12 44323
13 44324
14 44325
15 44326
16 44327
17 44328
18 44329
19 44330
20 44331
21 44332
22 44333
23 44334
24 44335
25 44336
26 44337
27 44338
28 44339
29 44340
30 44341
31 44342
32 44343
33 44344
34 44345
35 44346
36 44347
The vlookup takes each number in the initial sequence (6x7 layout), and brings back the corresponding date from col2 in the range, based on a match in col1.
When the first day of the month is a Monday, iferror(sequence(weekday(BB1,2),1)/0,)
generates a gap in col2 of the vlookup range. This is why col1 in the vlookup range has to start with 0
.
I've updated the sheet at https://docs.google.com/spreadsheets/d/1u_J7bmOFyDlYXhcL5dW3CHFJ1esySAKK_yPc6nFTdLA/edit#gid=68642071
Values on the calendar are dates so the formatting has to be d
.
If you want numbers, then use:
=arrayformula(
iferror(
vlookup(sequence(6,7),
{sequence(day(eomonth(Z3,0))+weekday(Z3,2),1,0),
{iferror(sequence(weekday(Z3,2),1)/0,);sequence(day(eomonth(Z3,0)),1)}},
2,false)
,))