Split strings by a certain delimiter and extract the output for further processing

I have a list of directory names (each in one line) that consist of the names of rubygems and their version.

I want to split them at the last hyphen in the string.

The folder-name string consists

of the name of the gem
and as the second part of a version number

How can one extract both for further processing and keep a relationship between the gem-name and the version-numbers established?

Given the list that find returns

find . -type d -regextype posix-extended -regex "^./[a-zA-Z0-9]+([-_]?[a-zA-Z0-9]+)*-[0-9]{1,3}(.[0-9]{1,3}){,3}\$"

My approach would have been nested arrays, like this

declare -A my_gems
my_gems[gem_name]=()
# append version numbers to the right hand side array

I need to further process it in the context of parsing user arguments to a script which contains of a gem_name and a list of versions.

Solution

A while read loop approach should be something like.

#!/usr/bin/env bash

declare -A my_gems
find . -type d -regextype posix-extended -regex "^./[a-zA-Z0-9]+([-_]?[a-zA-Z0-9]+)*-[0-9]{1,3}(.[0-9]{1,3}){,3}\$" | {
  while IFS= read -r line; do
    line=${line#*./}
    my_gems[${line%-*}]=${line##*-}
  done
}

declare -p my_gems

As suggested by @oguz using a Process Substitution.

#!/usr/bin/env bash

declare -A my_gems

while IFS= read -r line; do
  line=${line#*./}
  my_gems[${line%-*}]=${line##*-}
done < <(find . -type d -regextype posix-extended -regex "^./[a-zA-Z0-9]+([-_]?[a-zA-Z0-9]+)*-[0-9]{1,3}(.[0-9]{1,3}){,3}\$")

declare -p my_gems