I have this dataframe:
df <- data.frame(PatientID = c("3454","345","5","348","567","79"),
clas1 = c(1, 0, 5, NA, NA, 4),
clas2 = c(4, 1, 0, 3, 1, 0),
clas3 = c(1, NA, 0, 5, 5, 5), stringsAsFactors = F)
I would like to create a heatmap, with patient ID in the x axis and clas1, clas2 and clas3 in the y axis. The values represented in the heat map would be the raw value of each "clas". Here I post a drawing of what I would like
I apologise because I don't have available more colours to represent this, but this is only an example and any colour scale could be used. An important thing is that I would like to distinguish between zeros and NAs so ideally NAs have their own colour or appear in white (empty).
I hope this is understandable enough.
But any questions just ask
Many thanks!
I'll give 4 options, in all four you need to assign the rownames and remove the id column. I.e.:
df <- data.frame(PatientID = c("3454","345","5","348","567","79"),
clas1 = c(1, 0, 5, NA, NA, 4),
clas2 = c(4, 1, 0, 3, 1, 0),
clas3 = c(1, NA, 0, 5, 5, 5), stringsAsFactors = F)
rownames(df) <- df$PatientID
df$PatientID <- NULL
df
The output is:
> df
clas1 clas2 clas3
3454 1 4 1
345 0 1 NA
5 5 0 0
348 NA 3 5
567 NA 1 5
79 4 0 5
With base R (decent output):
heatmap(as.matrix(df))
With gplots (a bit ugly, but many more parameters to control):
library(gplots)
heatmap.2(as.matrix(df))
With heatmaply you have nicer defaults to use for the dendrograms (it also organizes them in a more "optimal" way).
You can learn more about the package here.
Static heatmap with heatmaply (better defaults, IMHO)
library(heatmaply)
ggheatmap(df)
Now with colored dendrograms
library(heatmaply)
ggheatmap(df, k_row = 3, k_col = 2)
With no dendrogram:
library(heatmaply)
ggheatmap(df, dendrogram = F)
Interactive heatmap with heatmaply (hover tooltip, and the ability to zoom - it's interactive!):
library(heatmaply)
heatmaply(df)
And anything you can do with the static ggheatmap you can also do with the interactive heatmaply version.