How can i use order_by() in combination with distinct() ?
I am having multiple same run_id with different end_time and trying to filter distinct run_id and order by end_time
data = list(table_name.objects.filter(experience=experience)\
.values('run_id', 'end_time').distinct('run_id').order_by('-end_time'))
Following is the error :-
django.db.utils.ProgrammingError: SELECT DISTINCT ON expressions must match initial ORDER BY expressions
However, the following ORM works fine without order_by
but I want the latest end_time
data = list(table_name.objects.filter(experience=experience).values('run_id', 'end_time').distinct('run_id'))
What is database?
Try:
data = list(table_name.objects.filter(experience=experience)\
.values('run_id', 'end_time').distinct('run_id').order_by('run_id', '-end_time'))[::1]