Changing reference to an outer function

Question

def foo():
    print(True)


def bar():
    foo()


def baz():
    def foo():
        print(False)

    foo()
    bar()


baz()

Outputs:

False
True

I need to make it output:

False
False  

By making bar call foo defined inside of baz without touching anything outside of baz itself.

Answer 1

for this, you need to overwrite foo's definition in the global scope. Just use the global keywbord:

def foo():
    print(True)

def bar():
    foo()

def baz():
    global foo

    old_foo = foo # if you want to backup the original definition of foo (optional)

    def foo():
        print(False)

    foo()
    bar()

    foo = old_foo # revert foo to its original state (optional)

    baz()

Output:

False
False