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pythonlistrangealphabetical

How to get a letter range in reversed order in Python?

I do realize this has already been addressed here (e.g., Is it possible to make a letter range in python?). Nevertheless, I hope this question was different.

The below code gives the range between any two alphabets

[chr(i) for i in range(ord('H'),ord('P'))]

Output

['H', 'I', 'J', 'K', 'L', 'M', 'N', 'O']

For the range of alphabets in reversed order, using reversed() returns the empty list

[chr(i) for i in range(ord('P'),ord('H'))]

# or 

[chr(i) for i in reversed(range(ord('P'),ord('H')))]

Output

[]

Expected output

['O', 'N', 'M', 'L', 'K', 'J', 'I', 'H']

How to get a letter range in reversed order in Python?

Solution

  • ord('P') is greater than ord('H'), so range(...) makes an empty range.

    To get a reverse letter list, do either of the following:

    • Make a forward list and apply reverse():

      reversed( range(ord('H'), ord('P')) )

    • Use the 3rd parameter to range():

      range(ord('P'), ord('H'), -1)