I have a dataset like original.
id <- c(1,1,1,2,3,3,3,4,4)
period <- c(1,1,2,2,1,2,3,1,3)
iso_1 <- c(1,0,0,0,1,1,0,1,1)
iso_2 <- c(1,1,1,0,0,1,0,1,1)
iso_3 <- c(1,0,1,0,0,1,0,0,1)
original <- data.frame(id, period, iso_1, iso_2, iso_3)
I like to modify the column names that have a pattern "iso_name" and add "_exp", so it looks like "iso_name_exp". The new dataset looks as follows:
iso_1_exp <- c(1,0,0,0,1,1,0,1,1)
iso_2_exp <- c(1,1,1,0,0,1,0,1,1)
iso_3_exp <- c(1,0,1,0,0,1,0,0,1)
new <- data.frame(id, period, iso_1_exp, iso_2_exp, iso_3_exp)
I did try the following line:
n <- ncol(original)
colnames(original)[,3:n] <- paste0(colnames(original)[,3:n],"_exp")
However it didn't make the trick.
Any idea? Thank you
Using dplyr :
library(dplyr)
original %>% rename_with(~paste0(., '_exp'), starts_with('iso'))
# id period iso_1_exp iso_2_exp iso_3_exp
#1 1 1 1 1 1
#2 1 1 0 1 0
#3 1 2 0 1 1
#4 2 2 0 0 0
#5 3 1 1 0 0
#6 3 2 1 1 1
#7 3 3 0 0 0
#8 4 1 1 1 0
#9 4 3 1 1 1
Base R :
cols <- grep('^iso', names(original))
names(original)[cols] <- paste0(names(original)[cols], '_exp')