I have the following data.frame
and i would like to multiply only the numeric
columns by a scalar
value.
library(tidyverse)
library(lubridate)
set.seed(123)
D1 <- data.frame(Date = seq(as.Date("2001-01-01"), to= as.Date("2001-01-10"), by="day"),
A1= runif(10,1,5),
B2 = runif(10,3,6),
C9 = runif(10,2,5))
I tried the following but it eliminate the Date
column
D <- D1 %>%
select(,c(2:4))*1000
Also this one remove the Date
column as well.
D <- D1 %>%
select_if(is.numeric)*1000
Are there any option that would keep the Date
column and does the multiplication ?
I hope this is what you are looking for:
library(dplyr)
D1 %>%
mutate(across(where(is.numeric), ~ .x * 1000))
Date A1 B2 C9
1 2001-01-01 3915.198 5360.962 3216.361
2 2001-01-02 1984.007 3316.846 4443.792
3 2001-01-03 2888.303 5870.227 4606.728
4 2001-01-04 1955.763 5771.595 3273.241
5 2001-01-05 1533.243 3205.139 3254.499
6 2001-01-06 3129.899 4899.974 3063.600
7 2001-01-07 1873.876 5107.482 4142.117
8 2001-01-08 3807.380 5759.612 2448.172
9 2001-01-09 1396.257 5009.001 4648.551
10 2001-01-10 1280.629 5441.055 4858.487