In the following data frame, how can I replace all 1
by 2
and all 2
by 1
, and keep 3
as it is
mydf=structure(list(x1 = c(1L, 2L, 3L, 1L), x2 = c(2L, 1L, 2L, 3L),
x3 = c(1L, 2L, 2L, 1L), x4 = c(1L, 2L, 1L, 1L)), row.names = 5:8, class = "data.frame")
mydf
x1 x2 x3 x4
5 1 2 1 1
6 2 1 2 2
7 3 2 2 1
8 1 3 1 1
Any kind of help is appreciated.
Base R :
mydf[] <- lapply(mydf, function(x) ifelse(x == 1, 2, ifelse(x == 2, 1, x)))
dplyr
:
library(dplyr)
mydf %>%
mutate(across(.fns = ~case_when(. == 2 ~ 1L,. == 1 ~ 2L, TRUE ~ .)))
# x1 x2 x3 x4
#5 2 1 2 2
#6 1 2 1 1
#7 3 1 1 2
#8 2 3 2 2