I have two arrays of known lengths:
let left: [u8; 2] = [1, 2];
let right: [u8; 3] = [3, 4, 5];
My first attempt:
let whole: [u8; 5] = left + right;
fails with the error:
error[E0369]: cannot add `[u8; 2]` to `[u8; 3]`
--> /home/fadedbee/test.rs:25:29
|
25 | let whole: [u8; 5] = left + right;
| ---- ^ ----- [u8; 3]
| |
| [u8; 2]
Likewise:
let whole: [u8; 5] = left.concat(right);
fails with:
error[E0599]: the method `concat` exists for array `[u8; 2]`, but its trait bounds were not satisfied
--> /home/fadedbee/test.rs:25:29
|
25 | let whole: [u8; 5] = left.concat(right);
| ^^^^^^ method cannot be called on `[u8; 2]` due to unsatisfied trait bounds
|
= note: the following trait bounds were not satisfied:
`<[u8] as std::slice::Concat<_>>::Output = _`
I'm currently using an expression of the form:
let whole: [u8; 5] = [left[0], left[1], right[0], right[1], right[2]];
but this is dozens of elements for my actual use-case and is prone to typos.
@Emoun kindly pointed out that I'd misused concat
.
Trying it properly:
let whole: [u8; 5] = [left, right].concat();
I get:
error[E0308]: mismatched types
--> /home/fadedbee/test.rs:32:31
|
32 | let whole: [u8; 5] = [left, right].concat();
| ^^^^^ expected an array with a fixed size of 2 elements, found one with 3 elements
|
= note: expected type `[u8; 2]`
found array `[u8; 3]`
How do I concatenate arrays of known lengths into a fixed length array?
I guess there is a better answer, but you can do like this:
fn main() {
let left: [u8; 2] = [1, 2];
let right: [u8; 3] = [3, 4, 5];
let whole: [u8; 5] = {
let mut whole: [u8; 5] = [0; 5];
let (one, two) = whole.split_at_mut(left.len());
one.copy_from_slice(&left);
two.copy_from_slice(&right);
whole
};
println!("{:?}", whole);
}