So, I have this code below:
from sympy import Symbol, solve, nsolve
x1 = Symbol('x1')
x2 = Symbol('x2')
w1 = Symbol('w1')
w2 = Symbol('w2')
eq1 = w1 + w2
eq2 = (w1 * x1) + (w2 * x2)
eq3 = (w1 * x1**2) + (w2 * x2**2)
eq4 = (w1 * x1**3) + (w2 * x2**3)
print(nsolve((eq1, eq2, eq3, eq4), (x1, x2, w1, w2), (2, 0, 2/3, 0)))
For this question:
Which gives me this as a response:
x = findroot(f, x0, J=J, **kwargs)
File "C:\Users\Sabri\AppData\Local\Packages\PythonSoftwareFoundation.Python.3.8_qbz5n2kfra8p0\LocalCache\local-packages\Python38\site-packages\mpmath\calculus\optimization.py", line 969, in findroot
for x, error in iterations:
File "C:\Users\Sabri\AppData\Local\Packages\PythonSoftwareFoundation.Python.3.8_qbz5n2kfra8p0\LocalCache\local-packages\Python38\site-packages\mpmath\calculus\optimization.py", line 660, in __iter__
s = self.ctx.lu_solve(Jx, fxn)
File "C:\Users\Sabri\AppData\Local\Packages\PythonSoftwareFoundation.Python.3.8_qbz5n2kfra8p0\LocalCache\local-packages\Python38\site-packages\mpmath\matrices\linalg.py", line 226, in lu_solve
A, p = ctx.LU_decomp(A)
File "C:\Users\Sabri\AppData\Local\Packages\PythonSoftwareFoundation.Python.3.8_qbz5n2kfra8p0\LocalCache\local-packages\Python38\site-packages\mpmath\matrices\linalg.py", line 142, in LU_decomp
ctx.swap_row(A, j, p[j])
File "C:\Users\Sabri\AppData\Local\Packages\PythonSoftwareFoundation.Python.3.8_qbz5n2kfra8p0\LocalCache\local-packages\Python38\site-packages\mpmath\matrices\matrices.py", line 876, in swap_row
A[i,k], A[j,k] = A[j,k], A[i,k]
File "C:\Users\Sabri\AppData\Local\Packages\PythonSoftwareFoundation.Python.3.8_qbz5n2kfra8p0\LocalCache\local-packages\Python38\site-packages\mpmath\matrices\matrices.py", line 490, in __getitem__
if key[0] >= self.__rows or key[1] >= self.__cols:
TypeError: '>=' not supported between instances of 'NoneType' and 'int'
Following the documentation here:
https://docs.sympy.org/latest/modules/solvers/solvers.html
It's not very clear what is causing the issue, except one of the variables may be None. On Google, a lot of the issues with a similar error are explicitly shown, which is not the case here. Any suggestions?
Edit: I get this answer:
Using this code:
from scipy.optimize import fsolve
def func(p):
x1, x2, w1, w2 = p
return (w1 + w2, (w1 * x1) + (w2 * x2), (w1 * x1**2) + (w2 * x2**2), (w1 * x1**3) + (w2 * x2**3))
x1, x2, w1, w2 = fsolve(func, (2, 0, 2/3, 0))
print(x1, x2, w1, w2)
So the code should return a result, but I'm not sure why it doesn't work for Sympy. Thanks!
nsolve()
, the RHS are all zeros. Non-zeros terms on RHS are moved (2, 0, 2/3, 0) to LHS.nsolve()
is the initial guess close to the solution. (x1,x2,w1,w2) = (-1,1,1,1)
in the interval [-1,1]
with equal weights. Output:
w1 + w2 - 2
w1*x1 + w2*x2
w1*x1**2 + w2*x2**2 - 0.666666666666667
w1*x1**3 + w2*x2**3
Matrix([[-0.577350269189626], [0.577350269189626], [1.00000000000000], [1.00000000000000]])
The results agree with the n=2
case on table in Wikipedia.
Code:
from sympy import Symbol, solve, nsolve
x1 = Symbol('x1')
x2 = Symbol('x2')
w1 = Symbol('w1')
w2 = Symbol('w2')
eq1 = w1 + w2 - 2
eq2 = (w1 * x1) + (w2 * x2) - 0
eq3 = (w1 * x1**2) + (w2 * x2**2) - 2 / 3
eq4 = (w1 * x1**3) + (w2 * x2**3) - 0
print(eq1, eq2, eq3, eq4, sep='\n')
print(nsolve((eq1, eq2, eq3, eq4), (x1, x2, w1, w2), (-1, 1, 0.5, 0.5)))