I am trying to create the dict for this list of lists contains tuples. The purpose is to filter the needed tuples into the final list.
What I have tried so far:
dict_1 = dict()
for val,sim in result:
dict_1.setdefault(val, [])
print(result)
It works fine when I look into result and unpack two values (val,sim). But every time it is not the same case i will get, there could be multiple values to unpack and then it gives this error:
ValueError: too many values to unpack (expected 2).
How can make the above loop for val,sim in result: flexible?
This is the input format:
[[(1.0, 2481), (0.125, 5)], [(1.0, 2481), (0.10526315789473684, 1), (0.0, 5), (0.0, 4), (0.0, 3), (0.0, 2)], [(1.0, 2481), (0.11764705882352941, 2), (0.0, 5), (0.0, 4), (0.0, 3), (0.0, 1)], [(1.0, 2481), (0.13333333333333333, 3), (0.0, 5), (0.0, 4), (0.0, 2), (0.0, 1)], [(1.0, 2481), (0.1, 4), (0.0, 5), (0.0, 3), (0.0, 2), (0.0, 1)]]
My ultimate goal is to make the dict first and then start filtering the tuples i am only interested in the tuples [(value,sim), (value,sim)] which have a specific value sim but before doing that I am stuck in above part.
Desired output:
[(1.0, 2481), (0.125, 5), (0.10526315789473684, 1),(0.11764705882352941, 2), (0.13333333333333333, 3), (0.1, 4)]
I am just a beginner. I understand this might not be the correct way to ask question. But any kind of little guidance in right direction would be appreciated!
You can try nested slicing:
a = [[(1.0, 2481), (0.125, 5)],
[(1.0, 2481), (0.10526315789473684, 1), (0.0, 5), (0.0, 4), (0.0, 3), (0.0, 2)],
[(1.0, 2481), (0.11764705882352941, 2), (0.0, 5), (0.0, 4), (0.0, 3), (0.0, 1)],
[(1.0, 2481), (0.13333333333333333, 3), (0.0, 5), (0.0, 4), (0.0, 2), (0.0, 1)],
[(1.0, 2481), (0.1, 4), (0.0, 5), (0.0, 3), (0.0, 2), (0.0, 1)]]
b = [a[0][0]] + [i[1] for i in a]
print(b)
Output:
[(1.0, 2481),
(0.125, 5),
(0.10526315789473684, 1),
(0.11764705882352941, 2),
(0.13333333333333333, 3),
(0.1, 4)]