Why do I get None in output in second line while using eval function?

Question

I am executing this line of code -

print(eval("print(2 +3)"))

but this instead of giving output as 5 gives output-

5
None

Answer 1

This is because you are giving eval() within print().

eval("(2 +3)")

This will return 5 as the function eval returns the value 5 which gets printed using the print()

However,

print(eval("print(2 +3)"))

Here inside the eval() you have used print(). So the inner print() prints the value 5 and the function eval() returns None as it has nothing to return. That None gets printed by the outer print()