This is the first time I’m asking question there so I’m sorry if is there anything I did wrong
Consider a file names '00.txt' and It contains the following.
ai_00_01_01 word01 word01(translated)
ai_00_01_02 word02 word02(translated)
...
ai_00_01_305 word305 word305(translated)
P.S. (translated) doesn’t mean there is really a () there, it is just a other language of that line’s word
I hope it changed to this :
word01 = word01(translated)
word02 = word02(translated)
...
word305 = word305(translated)
The things I tried:
cut -f 2- -d ' ' 00.txt > new_file.txt
"Give me the second and any other field beyond, using space as a delimiter, from the file.txt file and direct the output to new_file.txt" -by ivanivan in https://unix.stackexchange.com/questions/515249/how-to-delete-the-first-word-in-each-line-of-a-file (I think it’s means it is delete the text until the first space?Bad English sorry)
The code I tried just generate a new txt file while nth inside, and the 00 txt file didn’t change anything
Thanks to anyone to help this noob(aka myself)
Since your data is already separated by spaces, you can use a for /f loop with the default delimiters:
for /f "tokens=2,3" %%A in (00.txt) do echo %%A = %%B >>new_file.txt
This takes the second and third thing in each line, stores the second thing in %%A and the third thing in %%B, and then displays those two things in the format you mention in your question, redirecting it to new_file.txt. (Note that if you think you'll run the script more than once, you should add a line before this to delete new_file.txt or else you'll just append the lines to the end of the existing file.)