How to process double array with break using Python?

Question

I would like to process an array. Here is my previous question. How to process break an array in Python?

But I have another case and I refer to that answer, but I still can get my expectation result. Here is the case

Case 1

Folder = "D:\folder"
Name = ['gadfg5', '546sfdgh']
Ver = [None, 'hhdt5463']
Default = {'gadfg5': '6754435'}

Case 2

Folder = "D:\folder"
Name = ['gadfg5', '546sfdgh']
Ver = [None, 'None']
Default = {'gadfg5': '6754435', '546sfdgh': '98769786'}

Case 3

Folder = "D:\folder"
Name = ['gadfg5', '546sfdgh']
Ver = [g675436g, 'hhdt5463']
Default = {}

This is what I've tried:

for dn, dr, key in zip(Name, Ver, Default):
        if dr is None:
            Path = os.path.join(Folder, dn, Default[key])
            print("None",Path)
        else:
            Path = os.path.join(Folder, dn, dr)
            print("Not None", Path)

The output of CASE 3 is empty. But my expectation the output supposed to be:

D:\folder\gadfg5\g675436g
D:\folder\546sfdgh\hhdt5463

The output of CASE 2 is correct as my expectation which is:

D:\folder\gfg\6754435
D:\folder\546sfdgh\98769786

The output of CASE 1 only returns one path, like this:

D:\folder\gadfg5\6754435

But my expectation the output supposed to be like this:

 D:\folder\gadfg5\6754435
 D:\folder\546sfdgh\hhdt5463

Anyone can give me an idea, please. Thanks

Answer 1

what happens in case one is Name and Ver has two elements while dictionary Default has just one so when you zip them the output will have just one tuple: ('gadfg5', None, 'gadfg5')

Since the Default is a dictionary and its keys are the elements of Names we don't have to zip the three of them, instead try:

for dn, dr in zip(Name, Ver):
    if dr is None:
        Path = os.path.join(Folder, dn, Default[dn])
        print("None", Path)
    else:
        Path = os.path.join(Folder, dn, dr)
        print("Not None", Path)

The same logic applies to case 3

But there is an issue here let me demonstrate with another scenario, case 4:

Input:

Folder = "D:\Folder"
Name = ['gadfg5', '546sfdgh']
Ver = [None, 'hhdt5463']
Default = {}

Here dict Default is empty and Ver has a None element. This will throw a Key error at Default[dn]. So lets put a check for that too as follows:

for dn, dr in zip(Name, Ver):
    if dr is None:
        if dn in Default:  # check if Default contains the key dn
            Path = os.path.join(Folder, dn, Default[dn])
            print("None", Path)
        else:
            print('no default path for ', dn)
    else:
        Path = os.path.join(Folder, dn, dr)
        print("Not None", Path)