I'm trying to make a replacement in one pass with just one Regular expression but I think this is not possible at all. I'm using RegexBuddy but I'm always getting a catastrophic result and the expression cannot be evaluated.
For this text:
3 bla bla! !
4 yep yep! ?
FROM HERE
5 something randdom here!
6 perhaps some HTML there
TO HERE
7 what ever you like over here
8 and that's all folks!enter code here
I want to find a REGEX that replaces the line breaks by something else, let's say $$, but only on the section "from here" "to here". So basically the end result would be this:
3 bla bla! !
4 yep yep! ?
FROM HERE$$
$$
5 something randdom here!$$
$$
6 perhaps some HTML there$$
$$
TO HERE
7 what ever you like over here
8 and that's all folks!
I have this expression
((FROM HERE))((.*)(\n))+(TO HERE)
But I'm stuck so far trying to replace just the \n group by something else. I have done similar things in the past so I would say this should be possible in one go.
If this is not possible in regex I would simply create a C# console app to take first that text to a string and then replace each \n by $$, then put it back. That shouldn't be that difficult.
If you are using .NET, one option could be
(?s)(?<=^FROM HERE\b.*?)\r?\n\r?\n(?=.*?^TO HERE\b)
(?s) Inline modifier, dot matches a newline(?<=^FROM HERE\b.*?) Assert FROM HERE at the left at the start of the line\r?\n\r?\n Match 2 newlines(?=.*?^TO HERE\b) Assert TO HERE at the right at the start of the lineIn the replacement use (with double escapes $$)
\n$$$$\n
See a .NET regex demo and a C# demo.