python f-string include all numbers except 0 while making a file list

I want to make a list of files with extend() while ignoring any file name ending with 0 as in _file0.h5. I have this line for concatenating all the files into a list

data_files_0.extend(sorted(glob(f"{directory}*_file{filenum}.h5") ) )

I am trying to learn how to implement regex here and I tried

    filenum = re.match(r'[^0]')

by putting it above the previous line which gives the error TypeError: match() missing 1 required positional argument: 'string'

I am pretty confused here and all the examples of f-string with regex don't help me at all.

Solution

re.match won't automatically look for strings containing that pattern - you have to provide the string to it - that's the cause of the missing argument error. Example - re.match('[^0]', "abc0123") will check for matches in the string "abc0123" according to the pattern '[^0]'.

[^0] is likely wrong pattern here since this matches any and every character at any position in the string except for a 0. You might want to use something like .*0\.h5, which matches any string ending with '0.h5'. You can also check out regexr.com, which is a very helpful site for figuring out how regex patterns work in general.

For the other part of the problem - finding the files - you might have to just get all the filenames first, then check which ones end with 0 or not:

all_files = glob(f"{directory}*_file*.h5")
for f in all_files: 
    if not re.match('.*0\.h5', f):
        data_files_0.append(f)