Search code examples
algorithmdigitscounting

Finding the number of digits of an integer


What is the best method to find the number of digits of a positive integer?

I have found this 3 basic methods:

  • conversion to string

    String s = new Integer(t).toString(); 
    int len = s.length();
    
  • for loop

    for(long long int temp = number; temp >= 1;)
    {
        temp/=10;
        decimalPlaces++;
    } 
    
  • logaritmic calculation

    digits = floor( log10( number ) ) + 1;
    

where you can calculate log10(x) = ln(x) / ln(10) in most languages.

First I thought the string method is the dirtiest one but the more I think about it the more I think it's the fastest way. Or is it?


Solution

  • There's always this method:

    n = 1;
    if ( i >= 100000000 ) { n += 8; i /= 100000000; }
    if ( i >= 10000     ) { n += 4; i /= 10000; }
    if ( i >= 100       ) { n += 2; i /= 100; }
    if ( i >= 10        ) { n += 1; }