I suspect that this question is very easy to answer, and that the answer is "no". However, I want to make sure I'm not missing something.
Consider the following code:
sub f(:$a = 'foo') { say $a }
sub g(:$a) { f :$a }
g(); # OUTPUT: «(Any)»
Is there a good way to change the signature/body of &f or &g so that this prints foo instead of Any?
I know of two ways to get &f to use the default value for $a, but neither of them are great.
Option 1:
sub f(:$a = 'foo') { say $a }
multi g(:$a) { f :$a }
multi g() { f }
g(); # OUTPUT: «foo»
Option 2:
sub f(:$a = 'foo') { say $a }
sub g(:$a) { f |(:$a with $a) }
g(); # OUTPUT: «foo»
Neither of these feel like great approaches, so I'm hoping that someone can show me a more elegant approach that I'm missing. On the other hand, these both work, so it certainly won't be a big deal if this is just a slightly inelegant corner (and a very small one).
I would use either option 1, or if sub "g" always just calls sub "f", to create a capture of all parameters, and just pass that on:
sub f(str :$a = 'foo') { say $a }
sub g(|c) { f |c }
g a => "bar"; # "bar"
g; # "foo"