I have a dataframe with a column with the next caracteres:
head(example)
X. S10 tactagcaatacgcttgcgttcggtggttaagtatgtataatgcgcgggcttgtcgt
1 + AM \t\ttgctatcctgacagttgtcacgctgattggtgtcgttacaatctaacgcatcgccaa
2 + AR \t\tgtactagagaactagtgcattagcttatttttttgttatcatgctaaccacccggcg
3 + DE \taattgtgatgtgtatcgaagtgtgttgcggagtagatgttagaatactaacaaactc
So I want replace each letter by specific chain. For example: when it appears "a" i want put 0,0,0,1. But I get it
str_replace_all(example, "[a]", c("0","0","0","1")) [1] "tgct0tcctg0c0gttgtc0cgctg0ttggtgtcgtt0c00tct00cgc0tcgcc00"
Also I need separate each value in one column.
We can use a named vector with str_replace_all
library(stringr)
str_replace_all(example, setNames( c('0001', '1000'), c('a', 't')))
It replaces the lettters 'a', 't' with the values '0001' and '1000' respectively