Get all searched strings only

Question

I have a big file with long lines. I want to get the values matching my regex only.

My line:

XXXXXXXXXXXXXX;XXXXXXXXXXXX;XXXXXXXXXXXXXXXXX;666=0;XXXXXXXXXXXXXX;XXXXXXXXXX;XXX

I need to get only the value right after 665 in all lines. example: ;665=.;

so results should look like:

;665=1;
;665=5;
;665=B;
;665=AB;

And not the whole lines. The reason is that the result is always truncated in the search window

Answer 1

• Ctrl+H
• Find what: ^.+(;666=[^;\r\n]+;).+$
• Replace with: $1
• CHECK Wrap around
• CHECK Regular expression
• UNCHECK . matches newline
• Replace all

Explanation:

^           # beginning of line
    .+          # 1 or more any character but newline
    (           # group 1
        ;666=       # literally
        [^;\r\n]+   # 1 or more non semicolon and non linebreak
        ;           # a semicolon
    )           # end group
    .+          # 1 or more any character but newline
$           # end of line

Screenshot (before):

Screenshot (after):