Edit flat file to have a specific number of characters on each line?

I would like to create a batch file that converts every line in a flat file to e specific amount of characters (add spaces at the end of every row).

Example: I have a text file called "text.txt", and it looks like this:

I would like to run a batch file on it and recieve the following (all lines are 7 characters long):

1......
22.....
333....
4444...
55555..

(I had to replace my spaces with dots to make it visible)

Is this possible, and how?

Update:

Cool, that works perfect.

Is it also possible to convert a blank line (just CRLF) to 7 spaces? When I run the above on a file with empty lines they are deleted.

Thanks!

EDIT: Just to clarify, this is the file:

And I want to recieve:

1......
22.....
.......
333....
22.....
.......
1......
4444...
55555..

Thanks again!

Update 2:

Andriys answer is getting me a few steps forward. I've got a few issues though. If I leave the # sign out, the output will be like this (still periods instead of spaces):

1.......
22......
ECHO is off.
333.....
22......
ECHO is off.
1.......
4444....
55555...

And if a line starts with a space it will be outputted as:

ECHO is off.

Powershell is unfortunately not an option...

This might be a better example,
text.txt:

This is
 the input
file 
     I

 want to convert

Of course now we have to make the records longer, let's say 20 char.

Solution

The FOR loop does omit empty lines. This is by design. To work around that, you could use the following command:

FIND /N /V "" < sourcefile

It is considered that no line can match "" (empty string), so simply FIND "" < file would produce empty output. But the /V option causes the inversion of the output: instead of the lines that match the search string, FIND is to output those that do not match it. So FIND /V "" < file essentially causes FIND to output all the lines of file. And /N causes every line to be prepended with the line number, like this:

[number]text
[number]text
…

Accordingly, empty lines will look just like this:

[number]
[number]
…

So, now we are able to iterate over all the lines. We only need to remove all the [number] parts, then use @Dave's idea of appending the spaces and cutting out the first 7 characters. Here's a full script:

@ECHO OFF
FOR /F "delims=" %%L IN ('FIND /N /V "" ^<text.txt') DO CALL :process "%%L"
GOTO :EOF

:process
SET "line=%~1"
SET "line=%line:*]=%       "
ECHO(%line:~0,7%#

(The # character is only added for visual indication.)

UPDATE

Added ( just after ECHO. This solves the ECHO is off issue. Basically, you can use a number of different characters instead of (, like ., or , for instance. But, as shown in this answer, ( seems most reliable.

UPDATE 2

Added the "delims=" option to the FOR loop after /F to account for spaces in the text.