Consider the following class and mixin:
class Target(ClassThatUsesAMetaclass):
def foo(self):
pass
class Mixin:
def __init__(self):
self.foo() # type error: type checker doesn't know Mixin will have
# access to foo once in use.
class Combined(Mixin, Target):
def __init__(self):
Target.__init__(self)
Mixin.__init__(self)
I'm trying to avoid the type checker error in the above scenario. One option is this:
from typing import Protocol
class Fooable(Protocol):
def foo(self): ...
class Mixin(Fooable):
def __init__(self):
self.foo()
Would've worked great, except that Target
inherits from a class that uses a metaclass, so Combined
can't inherit from both Target
and Mixin
.
So now I'm trying an alternative, annotating self
in Mixin
:
from typing import TYPE_CHECKING
if TYPE_CHECKING:
from .this import Mixin, Target
Mixin_T = type('Mixin_T', (Mixin, Target), {})
class Mixin:
def __init__(self: Mixin_T):
self.foo() # No longer an error
class Combined(Mixin, Target):
def __init__(self):
Target.__init__(self)
Mixin.__init__(self) # Now this is an error: "Type[Mixin]" is not
# assignable to parameter "self"
# "Mixin" is incompatible with "Mixin_T"
So how am I supposed to win this aside from using # type: ignore
?
I found a very simple solution:
if TYPE_CHECKING:
from .this import Target
Mixin_T = Target
else:
Mixin_T = object
class Mixin(Mixin_T):
...
Now all of Target
's methods are recognized within Mixin
by the type checker, and there's no need to override the type of self
into something imcompatible with Mixin
. This might be a little awkward if the mixin is destined to all kinds of Target
classes, but for my uses this is perfectly acceptable, since my case is a group of mixins extending a very specific target class.