I've run into an issue in which I think should be easy to resolve, but for the life of me, I can't figure it out. Could be that it's really late; not sure.
So I have a shell script and I have an if statement that I need to run. The problem is that I have a function inside this bash script that I am using to actually build part of this find command inside the if statement. I want to know how I can do both, without receiving an error [: too many arguments.
Here's the current code:
if [ -n `find ./ `build_ext_names`` ];then
That's all I really need to post. I need to figure out how to run that build_ext_names inside that find command, which in-turn is inside the ifstatement
Michael Aaron Safyan has the right idea, but to fix the immediate problem you can just use the simpler $(command) construct instead of ```command` `` for command substitution. It allows for much simpler nesting:
if [ -n "$(find ./ "$(build_ext_names)")" ]; then