p [1,2,3].map(&:abs)
p [1,2,3].map(:abs)
p [1,2,3].reduce(&:gcd)
p [1,2,3].reduce(:gcd)
Can someone pls explain why line 2 will throw an error, but not line 4.
This isn't a general syntactic thing related to Symbol
or Symbol#&
. It's a special case built into the implementation of Enumerable#reduce
.