I am trying to prevent an error if the user tries to divide 10/'dog'. Even after using exception I still get error

Question

Still getting Type and Value Error

def my_divider(a,b):         
    try:return a/b 
    
    except ZeroDivisionError:
        return"Error: You cannot divide a number by 0"
    
    except TypeError:         
        a=float(a)
        b=float(b)
        return a/b
    
    except ValueError:
        return"Please enter an integer"
  
var1=10
var2='dog'
print(my_divider(var1,var2))

Answer 1

I'll echo what @dkamins is saying here but I need the rep so I'll take a stab here.

The code you're cooking looks so close, you'll kick yourself when you see it. Great use of the try except clause! You're looking like a python pro already. Yes, the error occurs when you try to assign b = float(b) when isinstance(b,str) but I see, I think, you trying to catch that exception. But since it is inline with a separate try-except clause, it is behaving how you're seeing. So, something like:

def my_divisor(a,b):

  try:

    return a/b

  except ZeroDivisionError:

    print("You cannot divide by the number 0")

    return None
  
  except TypeError:

    try:

      a = float(a)
      b = float(b)

      return a/b

    except ValueError:

      print('Error converting type of a, b to numeric. Just put in some numbers, pls')

      return None

Be careful!!! We didn't handle something here. What would my_divisor(40,"0") return? I think you got it from here friend!